Cuba, New York

town in Allegany County, New York, United States

Cuba is a town in Allegany County, New York, United States. As of the 2020 United States Census, the total population was 3,126.[2]

Cuba, New York
Town center along Genesee Street
Town center along Genesee Street
Cuba is located in New York
Cuba
Cuba
Location of Cuba in New York
Cuba is located in the United States
Cuba
Cuba
Cuba (the United States)
Coordinates: 42°13′04″N 78°16′31″W / 42.21778°N 78.27528°W / 42.21778; -78.27528
CountryUnited States
StateNew York
CountyAllegany
Area
 • Total35.80 sq mi (92.73 km2)
 • Land35.10 sq mi (90.91 km2)
 • Water0.70 sq mi (1.82 km2)
Population
 • Total3,126
 • Density89.06/sq mi (34.39/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code36-003-19367
Websitehttps://www.cubany.org/

References

change
  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 7, 2024.
  2. 2.0 2.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Cuba town, Allegany County, New York". United States Census Bureau. Retrieved March 7, 2024.