Jefferson, South Dakota

city in South Dakota, United States

Jefferson is a city in the southeastern part of the U.S. state of South Dakota. It is located in Union County, and 475 people lived there at the 2020 census.[4] Jefferson became a city in 1895.[5]

Jefferson, South Dakota
Location in Union County and the state of South Dakota
Location in Union County and the state of South Dakota
Coordinates: 42°36′15″N 96°33′58″W / 42.60417°N 96.56611°W / 42.60417; -96.56611
CountryUnited States
StateSouth Dakota
CountyUnion
Incorporated1895[1]
Area
 • Total0.51 sq mi (1.32 km2)
 • Land0.51 sq mi (1.32 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation1,116 ft (340 m)
Population
 • Total475
 • Density931.37/sq mi (359.27/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
57038
Area code605
FIPS code46-32700
GNIS feature ID1267441[3]

References

change
  1. "SD Towns" (PDF). South Dakota State Historical Society. Archived from the original (PDF) on 2010-02-10. Retrieved 2010-02-13.
  2. "ArcGIS REST Services Directory". United States Census Bureau. Retrieved October 15, 2022.
  3. 3.0 3.1 U.S. Geological Survey Geographic Names Information System: Jefferson, South Dakota
  4. 4.0 4.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson city, South Dakota". United States Census Bureau. Retrieved February 15, 2024.
  5. "SD Towns" (PDF). South Dakota State Historical Society. Retrieved 2014-02-16.