Jefferson, South Dakota
city in South Dakota, United States
Jefferson is a city in the southeastern part of the U.S. state of South Dakota. It is located in Union County, and 475 people lived there at the 2020 census.[4] Jefferson became a city in 1895.[5]
Jefferson, South Dakota | |
---|---|
![]() Location in Union County and the state of South Dakota | |
Coordinates: 42°36′15″N 96°33′58″W / 42.60417°N 96.56611°W | |
Country | United States |
State | South Dakota |
County | Union |
Incorporated | 1895[1] |
Area | |
• Total | 0.51 sq mi (1.32 km2) |
• Land | 0.51 sq mi (1.32 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 1,116 ft (340 m) |
Population | |
• Total | 475 |
• Density | 931.37/sq mi (359.27/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 57038 |
Area code | 605 |
FIPS code | 46-32700 |
GNIS feature ID | 1267441[3] |
References
change- ↑ "SD Towns" (PDF). South Dakota State Historical Society. Archived from the original (PDF) on 2010-02-10. Retrieved 2010-02-13.
- ↑ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved October 15, 2022.
- ↑ 3.0 3.1 U.S. Geological Survey Geographic Names Information System: Jefferson, South Dakota
- ↑ 4.0 4.1 "Profile of General Population and Housing Characteristics: 2020 Demographic Profile Data (DP-1): Jefferson city, South Dakota". United States Census Bureau. Retrieved February 15, 2024.
- ↑ "SD Towns" (PDF). South Dakota State Historical Society. Retrieved 2014-02-16.